Optimal. Leaf size=195 \[ \frac{\left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac{b+2 c x^3}{2 \sqrt{c} \sqrt{a+b x^3+c x^6}}\right )}{8 c^{7/2}}-\frac{\left (b \left (15 b^2-52 a c\right )-2 c x^3 \left (5 b^2-12 a c\right )\right ) \sqrt{a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}-\frac{2 b x^6 \sqrt{a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}+\frac{2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt{a+b x^3+c x^6}} \]
[Out]
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Rubi [A] time = 0.546425, antiderivative size = 195, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3 \[ \frac{\left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac{b+2 c x^3}{2 \sqrt{c} \sqrt{a+b x^3+c x^6}}\right )}{8 c^{7/2}}-\frac{\left (b \left (15 b^2-52 a c\right )-2 c x^3 \left (5 b^2-12 a c\right )\right ) \sqrt{a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}-\frac{2 b x^6 \sqrt{a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}+\frac{2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt{a+b x^3+c x^6}} \]
Antiderivative was successfully verified.
[In] Int[x^14/(a + b*x^3 + c*x^6)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 47.4993, size = 182, normalized size = 0.93 \[ - \frac{2 b x^{6} \sqrt{a + b x^{3} + c x^{6}}}{3 c \left (- 4 a c + b^{2}\right )} + \frac{2 x^{9} \left (2 a + b x^{3}\right )}{3 \left (- 4 a c + b^{2}\right ) \sqrt{a + b x^{3} + c x^{6}}} - \frac{\left (b \left (- 39 a c + \frac{45 b^{2}}{4}\right ) - \frac{3 c x^{3} \left (- 12 a c + 5 b^{2}\right )}{2}\right ) \sqrt{a + b x^{3} + c x^{6}}}{9 c^{3} \left (- 4 a c + b^{2}\right )} + \frac{\left (- 4 a c + 5 b^{2}\right ) \operatorname{atanh}{\left (\frac{b + 2 c x^{3}}{2 \sqrt{c} \sqrt{a + b x^{3} + c x^{6}}} \right )}}{8 c^{\frac{7}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**14/(c*x**6+b*x**3+a)**(3/2),x)
[Out]
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Mathematica [A] time = 0.268702, size = 147, normalized size = 0.75 \[ \frac{\sqrt{a+b x^3+c x^6} \left (-\frac{8 \left (a^2 c \left (2 c x^3-3 b\right )+a b^2 \left (b-4 c x^3\right )+b^4 x^3\right )}{\left (b^2-4 a c\right ) \left (a+b x^3+c x^6\right )}-7 b+2 c x^3\right )}{12 c^3}+\frac{\left (5 b^2-4 a c\right ) \log \left (2 \sqrt{c} \sqrt{a+b x^3+c x^6}+b+2 c x^3\right )}{8 c^{7/2}} \]
Antiderivative was successfully verified.
[In] Integrate[x^14/(a + b*x^3 + c*x^6)^(3/2),x]
[Out]
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Maple [F] time = 0.06, size = 0, normalized size = 0. \[ \int{{x}^{14} \left ( c{x}^{6}+b{x}^{3}+a \right ) ^{-{\frac{3}{2}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^14/(c*x^6+b*x^3+a)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^14/(c*x^6 + b*x^3 + a)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.351939, size = 1, normalized size = 0.01 \[ \left [\frac{4 \,{\left (2 \,{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{9} - 5 \,{\left (b^{3} c - 4 \, a b c^{2}\right )} x^{6} - 15 \, a b^{3} + 52 \, a^{2} b c -{\left (15 \, b^{4} - 62 \, a b^{2} c + 24 \, a^{2} c^{2}\right )} x^{3}\right )} \sqrt{c x^{6} + b x^{3} + a} \sqrt{c} - 3 \,{\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{6} + 5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} +{\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{3}\right )} \log \left (4 \, \sqrt{c x^{6} + b x^{3} + a}{\left (2 \, c^{2} x^{3} + b c\right )} -{\left (8 \, c^{2} x^{6} + 8 \, b c x^{3} + b^{2} + 4 \, a c\right )} \sqrt{c}\right )}{48 \,{\left ({\left (b^{2} c^{4} - 4 \, a c^{5}\right )} x^{6} + a b^{2} c^{3} - 4 \, a^{2} c^{4} +{\left (b^{3} c^{3} - 4 \, a b c^{4}\right )} x^{3}\right )} \sqrt{c}}, \frac{2 \,{\left (2 \,{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{9} - 5 \,{\left (b^{3} c - 4 \, a b c^{2}\right )} x^{6} - 15 \, a b^{3} + 52 \, a^{2} b c -{\left (15 \, b^{4} - 62 \, a b^{2} c + 24 \, a^{2} c^{2}\right )} x^{3}\right )} \sqrt{c x^{6} + b x^{3} + a} \sqrt{-c} + 3 \,{\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{6} + 5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} +{\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{3}\right )} \arctan \left (\frac{{\left (2 \, c x^{3} + b\right )} \sqrt{-c}}{2 \, \sqrt{c x^{6} + b x^{3} + a} c}\right )}{24 \,{\left ({\left (b^{2} c^{4} - 4 \, a c^{5}\right )} x^{6} + a b^{2} c^{3} - 4 \, a^{2} c^{4} +{\left (b^{3} c^{3} - 4 \, a b c^{4}\right )} x^{3}\right )} \sqrt{-c}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^14/(c*x^6 + b*x^3 + a)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{14}}{\left (a + b x^{3} + c x^{6}\right )^{\frac{3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**14/(c*x**6+b*x**3+a)**(3/2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{14}}{{\left (c x^{6} + b x^{3} + a\right )}^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^14/(c*x^6 + b*x^3 + a)^(3/2),x, algorithm="giac")
[Out]